a^2+27a-58=0

Solution for a^2+27a-58=0 equation:

a^2+27a-58=0

a = 1; b = 27; c = -58;
Δ = b2-4ac
Δ = 272-4·1·(-58)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-31}{2*1}=\frac{-58}{2}
=-29
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+31}{2*1}=\frac{4}{2}
=2
$